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A sample of liquid H₂O of mass 18.0 g is injected into an evacuated 7.6 L flask maintained at 27.0 °C. If vapour pressure of H₂O at 27 °C is 24.63 mm Hg, what weight percentage of the water will be vapourised when the system comes to equilibrium? Assume water vapours behaves as an ideal gas. The volume occupied by the liquid water is negligible compared to the volume of the container:

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Detailed Solution

Initial mass of $H_{2} O (l) = 18 g :$
$n_{H_{2} O} (g) = \frac{(\frac{24.63}{760}) \times 7.6}{0.0821 \times 300} \Rightarrow 0.01$
$% wt. of H_{2} O vaporised = \frac{0.01 \times 18}{18} \times 100 \Rightarrow 1 %$

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