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Q.

A sample of one mole of gas at temperature T is adiabatically compressed to half of its volume. The work done on the gas in the process is (given γ=32 )

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a

W=RT(222)

b

W=RT(222)

c

W=RT(22)

d

W=RT(22)

answer is A.

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Detailed Solution

For one mole of ideal gas, the work done in adiabatic process
W=Rr1[T1T2] but T1V1 γ1=T2V2γ1 
T2=T1(V1V2)γ1=(VV/2)3/21T=T(2)1/2=2T 
W=R321[T2T] 
W=2RT[12]W=RT(222)

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A sample of one mole of gas at temperature T is adiabatically compressed to half of its volume. The work done on the gas in the process is (given γ=32 )