A sample of oxygen at NTP has volume V and a sample of hydrogen at NTP has the volume 4V. Both the gases are mixed. If the speed of sound in hydrogen at NTP is 1270 m/s, that in mixture is

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950 m/s

635 m/s

317 m/s

830 m/s

answer is B.

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Detailed Solution

Molar mass of the mixture

$M = \frac{n 32 + 4 n (2)}{5 n} 1 \to H_{2} and 2 \to mixture A M = \frac{40}{5} = 8 \Rightarrow \frac{v_{1}}{v_{2}} = \sqrt{\frac{M_{2}}{M_{1}}} \frac{1270}{v_{2}} = \sqrt{\frac{8}{2}} \Rightarrow v_{2} = \frac{1270}{2} \Rightarrow= 635 {ms}^{- 1}$

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