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Q.

A sample of ozonised oxygen contains 90% by volume of oxygen. What will be the volume of the resulting gases when 120ml of such a sample is heated and then cooled to the original conditions of temperature and pressure ?

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a

100 ml

b

50 ml

c

126 ml

d

132 ml

answer is A.

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Detailed Solution

Volume of Ozonized oxygen = 120ml
Volume percentage of Oxygen = 90%
$Volume\;of\;Ozonized\;Oxygen\;=\left ( 120\times \frac{90}{100} \right )$
When heated and cooled all the Ozone converts to oxygen
$\large \\\\\mathop {2{O_3}}\limits_{12}^{2V} (g)\; \rightleftharpoons \;\mathop {3{O_2}}\limits_{'V'\;ml}^{3V} (g)\\\\V\; = \;12\; \times \;\frac{3}{2}\; = \;18ml$
Volume of oxygen formed due to the decomposition of Ozone = 18ml
After the process only oxygen gas is left after the process (108 + 18)ml
Volume of resulting gases (Oxygen) =126ml

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