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A sample of $^{14} {CO}_{2}$ was to be mixed with ordinary ${CO}_{2}$ for a biological tracer experiment. In order that $10 {cm}^{3}$ of diluted gas should have $10^{4}$ dis/min, what activity (in $μ Ci)$ ) of radio active carbon is needed to prepare 60 L of diluted gas at 1 atm and 273 K?
$[1 Ci = 3.7 \times 10^{10} dps]$

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$270 μ Ci$

$27 μ Ci$

$2.7 μ Ci$

$2700 μ Ci$

answer is B.

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Detailed Solution

Lets we have

$\frac{60 \times 10^{3}}{10} \times \frac{10^{4}}{60} \times \frac{1}{3.7 \times 10^{10}}$

$= 0.27 \times 10^{- 4} Ci$

$= 27 μ Ci$

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