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Q.

A sample of $H_{2}$ is collected over $H_{2} O$ at $23^{\circ} C$ and a pressure of $732 mm Hg$ has a volume of $245 mL$ . What volume would the dry $H_{2}$ occupy at $0^{\circ} C$ and 1 atm pressure?
[VP of $H_{2} O$ at $23^{\circ} C = 21 m m H g$ ]

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a

$211 m L$

b

$224 m L$

c

$249 m L$

d

$218 m L$

answer is A.

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Detailed Solution

$\frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}}$

$\frac{711 \times 245}{296}$

$= \frac{760 \times V}{273}$

$V = 211 mL$

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