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A sample of $H_{2} {SO}_{4}$ is labelled as 9.8% by weight. Its specific gravity is 1.8g/cc. Volume of this solution required to prepare 180 ml of 0.2 molar $H_{2} {SO}_{4}$ solution is

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20 mL

40 mL

10 mL

50 mL

answer is A.

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Detailed Solution

$M = \frac{% \times 10 \times d}{GMW}$

$= \frac{9.8 \times 10 \times 1.8}{98} = 1.8 M$

$M_{1} = 1.8 M M_{2} = 0.2$

$V_{1} = ? V_{2} = 180 mL$

$V_{1} = \frac{M_{2} V_{2}}{M_{1}}$

$= \frac{0.2 \times 180}{1.8} = 20 mL$

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