A satellite is in a circular equatorial orbit of a radius 7000km around the earth. If it is transferred to a circular orbit of double the radius:

	Column-I		Column- II
A	Angular momentum	P	Increases
B	Time period	Q	decreases
C	Potential energy	R	becomes double
D	Kinetic energy	S	becomes half

(a)  $L=mvr=m\left(\sqrt{\frac{GM}{e}}\right)r$

$L\infty \sqrt{r}$, , So the angular momemtum increases and becomes  $\sqrt{2}$  times

(b). $t^2\propto r^3$, so the time period increases

so the area covered by the satellite increases

(c)        $U=-\frac{GMm}{r}$

So, when r is doubled PE becomes half and increases

(d)  $KE=-\frac{GMm}{r}$

So, KE decreases and becomes half