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Q.

A satellite is moving in a circular orbit around the earth with a speed equal to half the escape speed from the earth. If ‘R’ is the radius of the earth, then the height of the satellite above the surface of the earth is                   

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a

2R

b

2R/3

c

R

d

R/2

answer is C.

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Detailed Solution

Given V0=12Ve

GMR+h=122GMR

After simplification

h=R

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