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Q.

A satellite is moving with a constant speed v in a circular orbit about the earth. An object of mass m is ejected from the satellite such that it just escapes from the gravitational pull of the earth. At the time of its ejection, the kinetic energy of the object is 

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a

12mv2

b

2mv2

c

mv2

d

3/2mv2

answer is B.

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Detailed Solution

In circular orbit of a satellite,

P. E = - 2 KE

=212mv2=−mv2

Just to escape from the gravitational pull, its total mechanical energy should be zero. Therefore, Its K E should be mv2

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