A satellite is orbiting the earth, if its distance from the earth is increased, its

Linear velocity or orbital velocity is $\mathrm{v}=\sqrt{\mathrm{GM}/\mathrm{r}}$ where r is the distance of the satellite from the centre of the earth. Therefore, v decreases as r is increased.
Also $\mathrm{v}=\mathrm{r\omega }$, where $\mathrm{\omega }$ is the angular velocity.

Therefore, $\mathrm{\omega }=\frac{\mathrm{v}}{\mathrm{r}}=\frac{1}{\mathrm{r}}\sqrt{\frac{\mathrm{GM}}{\mathrm{r}}}=\sqrt{\frac{\mathrm{GM}}{{\mathrm{r}}^3}}$

Thus, $\mathrm{\omega }$ decreases with increase in r. The time period of the satellite is given by

$\mathrm{T}=2\mathrm{\pi }\sqrt{\frac{{\mathrm{r}}^3}{\mathrm{GM}}}$

Thus, T increases as r is increased. Hence, the correct choices are (3) and (4).