A satellite is revolving in a circular orbit of radius R. Ratio of KE and its PE is (only magnitude)

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1:4

3:2

1:2

2:1

answer is D.

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Detailed Solution

$|P . E| = \frac{GMm}{R} - - - (1)$
$K . E = \frac{1}{2} {mv}_{0}^{2};$ where, $v_{0} = \sqrt{\frac{GM}{R}}$
$\begin{array}{l} K \cdot E = \frac{1}{2} m \frac{GM}{R} = \frac{1}{2} P \cdot E (from(1)) \\ \Rightarrow \frac{K \cdot E}{P . E} = \frac{1}{2} \end{array}$

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