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A satellite is seen after every 6 hours over the equator. It is known that is rotates opposite to that of earth’s direction. Then the angular velocity ( in radians per hour) of the satellite about the centre of earth will b

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a

$\frac{π}{2}$

b

$\frac{π}{3}$

c

$\frac{π}{4}$

d

$\frac{π}{8}$

answer is C.

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Detailed Solution

As the satellite is seen every 6hrs, we can conclude that the satellite rotation and satellite revolution are in opposite direction.

$\begin{array}{l} \frac{2 π}{T_{r e l}} = \frac{2 π}{T_{e a r t h}} + \frac{2 π}{T_{s a t e l l i t e}} \\ \Rightarrow \frac{2 π}{6} = \frac{2 π}{24} + \frac{2 π}{T_{s a t e l l i t e}} \Rightarrow ω_{s a t e l l i t e} = \frac{2 π}{T_{s a t e l l i t e}} = \frac{π}{4} \end{array}$

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