A satellite moves round the earth in a circular orbit of radius R making one revolution per day. A second satellite moving in a circular orbit, moves round the earth once in 8 days. The radius of the orbit of the second satellite is

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answer is B.

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Detailed Solution

$Given that, T_{1} = 1 day and T_{2} = 8 days$

$\begin{array}{l} ∴ \frac{T_{2}}{T_{1}} = {(\frac{r_{2}}{r_{1}})}^{3 / 2} \Rightarrow \frac{r_{2}}{r_{1}} = {(\frac{T_{2}}{T_{1}})}^{2 / 3} = {(\frac{8}{1})}^{2 / 3} = 4 \\ \Rightarrow r_{2} = 4 r_{1} = 4 R \end{array}$

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