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Q.

A satellite of earth of mass $'m'$ is taken from orbital radius $2 R$ to $3 R$ , then minimum work done is :-

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a

$\frac{G M m}{3 R}$

b

$\frac{G M m}{6 R}$

c

$\frac{G M m}{24 R}$

d

$\frac{G M m}{12 R}$

answer is B.

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Detailed Solution

$W = E_{2} - E_{1} = \frac{G M m}{2} (\frac{1}{2 R} - \frac{1}{3 R}) = \frac{G M m}{12 R}$

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