Potential energy of satellite at height  h  from the earth surface, 

P.E. = $-\frac{\mathrm{GMm}}{(\mathrm{R}+\mathrm{h})}=-\frac{{\mathrm{mg}}_0{\mathrm{R}}^2}{(\mathrm{R}+\mathrm{h})}\left(\because {\mathrm{g}}_0=\frac{\mathrm{GM}}{{\mathrm{R}}^2}\right)$

Kinetic energy (K.E.) =  $\frac{1}{2}{\mathrm{mv}}^2$

$\text{ Also, }\frac{m{v}^2}{(R+h)}=\frac{GMm}{(R+h{)}^2}\text{ or, }{v}^2=\frac{GM}{R+h}$…..(2)

K.E. = $\frac{\mathrm{GMm}}{2\left(\mathrm{R}+\mathrm{h}\right)}=\frac{{\mathrm{mg}}_0{\mathrm{R}}^2}{2(\mathrm{R}+\mathrm{h})}\left(\because {\mathrm{g}}_0=\frac{\mathrm{GM}}{{\mathrm{R}}^2}\right)$