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Q.

A satisfactory photographic print is obtained when the exposure time is 10 sec at a distance of 2 m from a 60 cd lamp. The time of exposure required for the same quality print at a distance of 4 m from a 120 cd lamp is 

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a

20 sec

b

10 sec

c

15 sec

d

5 sec

answer is D.

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Detailed Solution

I1D12t1=I2D22t2 Here D is constant and I=Lr2  So L1r12×t1=L2r22×t260(2)2×10=120(4)2×t20sec

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