A saturated aqueous solution of sucrose, $C_{12} H_{22} O_{11},$ , contains 525 g of sucrose (molar mass 342) per 100 g of water. What is the $C_{12} H_{22} O_{11} / H_{2} O$ molecular ratio in this solution?

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$\frac{5.25}{1}$

$\frac{0.276}{1}$

$\frac{1}{1}$

$\frac{1.54}{1}$

answer is D.

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Detailed Solution

$\frac{C_{12} H_{22} O_{11}}{H_{2} O}$ = $\frac{Molecules of C_{12} H_{22} O_{11}}{Molecules of H_{2} O}$

$\frac{N_{1} \times N_{A}}{N_{2} \times N_{A}} = \frac{N_{1}}{N_{A}}$

$\frac{(525 / 342)}{(16 / 18)}$

$= 0.276$

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