A saturated solution of sparingly soluble base Fe(OH)3 is found to have a specific conductance of 50×10−4 ohm−1 m−1.Given λeq∞FeCl3=10×10−3 Sm2 eq−1λeq∞NaCl=16×10−3 Sm2 eq−1λeq∞NaOH=23×10−3 Sm2 eq−1,specific conductance of water is negligible, Then

λ Fe(OH)3∘=λFeCl3∘+λNaOH∘−λNaCl∘, μFe(OH)3∘=3λFe(OH)3∘ μFe(OH)3∘=k×1000/S Ksp=2754 In the presence of OH−ions S=Ksp/[OH−]3

A saturated solution of sparingly soluble base Fe(OH)3 is found to have a specific conductance of 50×10−4 ohm−1 m−1.Given λeq∞FeCl3=10×10−3 Sm2 eq−1λeq∞NaCl=16×10−3 Sm2 eq−1λeq∞NaOH=23×10−3 Sm2 eq−1,specific conductance of water is negligible, Then

λ Fe(OH)3∘=λFeCl3∘+λNaOH∘−λNaCl∘, μFe(OH)3∘=3λFe(OH)3∘ μFe(OH)3∘=k×1000/S Ksp=2754 In the presence of OH−ions S=Ksp/[OH−]3

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A saturated solution of sparingly soluble base $Fe {(OH)}_{3}$ is found to have a specific conductance of $50 \times 10^{- 4} {ohm}^{- 1} m^{- 1}$ .
Given $λ_{eq}^{\infty} {FeCl}_{3} = 10 \times 10^{- 3} {Sm}^{2} {eq}^{- 1}$
$λ_{eq}^{\infty} NaCl = 16 \times 10^{- 3} {Sm}^{2} {eq}^{- 1}$
$λ_{eq}^{\infty} NaOH = 23 \times 10^{- 3} {Sm}^{2} {eq}^{- 1},$ specific conductance of water is negligible, Then

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K_sp of $Fe {(OH)}_{3}$ is $2.7 \times 10^{- 15}$

K_sp of $Fe {(OH)}_{3}$ is $2.2 \times 10^{- 10}$

solubility of Fe(OH)₃ in a solution of pH = 13 is ${2.7×10}^{- 12}$

solubility of Fe(OH)₃ in a solution of pH = 13 is $2.2 \times 10^{- 7}$

answer is A, C.

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Detailed Solution

$λ_{^{Fe {(OH)}_{3}}}^{\circ} = λ_{{FeCl}_{3}}^{\circ} + λ_{NaOH}^{\circ} - λ_{NaCl}^{\circ}, μ_{Fe {(OH)}_{3}}^{\circ} = 3 λ_{Fe {(OH)}_{3}}^{\circ} μ_{Fe {(OH)}_{3}}^{\circ} = k \times 1000 / S K_{sp} = 275^{4} In the presence of {OH}^{-} ions S = K_{sp} / {[{OH}^{-}]}^{3}$