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A scientist measuring the age of a wooden place found in pre – historic structure finds that the ratio of $_{6}^{14} C$ to ordinary carbon is only (1/4)th that found in the cells of living plants. If half life of $_{6}^{14} C$ is 5700 years the age of wood is

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22800 years

2850 years

11400 years

5700 years

answer is C.

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Detailed Solution

$\frac{1}{4} = \frac{1}{2^{n}} \Rightarrow n = 2$
Time taken for two half lives $= 2 \times 5700$
$= 11400 years$

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