A screen is at a distance of 2m from narrow slits that are illuminated with light of 6000 A0. The first maximum lies at 0.005cm on either side of the central maximum, then the distance between the slits will be (in cm )

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A screen is at a distance of 2m from narrow slits that are illuminated with light of $6000 A^{0}$ . The first maximum lies at 0.005cm on either side of the central maximum, then the distance between the slits will be (in cm )

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answer is 2.4.

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Detailed Solution

$y = \frac{λD}{d}$

$= \frac{6000 \times 10^{- 10} \times 2}{5 \times 10^{- 5}}$

$= 2.4 \times 10^{- 2} m = 2.4 c m$

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