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A screen is placed at 50 cm from a single slit, which is illuminated with 600 nm light. If separation between the first and third minima in the diffraction pattern is 3.0 mm, then width of the slit is:

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0.4 mm

0.1 mm

0.3 mm

0.2 mm

answer is D.

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Detailed Solution

$y_{3} - y_{1} = \frac{3 λ x}{α} - \frac{λ x}{α}$

$\Rightarrow 3 \times 10^{- 3} = \frac{2 \times 600 \times 10^{- 9} \times 0.5}{α}$

$\Rightarrow a = 0.2 nm$

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