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Q.

A screw gauge has 100 divisions on the circular scale and linear distance travelled by the head scale is 5mm in 10 complete rotation of circular scale. When nothing is placed between its studs, the zero of circular scale is 26 divisions above the reference line, it means zero error is-26 divisions on the circular scale. If the negative
Zero error of screw gauge is x mm, the value of x is………..

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Detailed Solution

Pitch $\frac{2 m m}{10} = 0.5 m m$
Least count $= \frac{0.5}{100} = 0.5 m m$
Negative zero error= $26 \times 0.005 = 0.13 m m$

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A screw gauge has 100 divisions on the circular scale and linear distance travelled by the head scale is 5mm in 10 complete rotation of circular scale. When nothing is placed between its studs, the zero of circular scale is 26 divisions above the reference line, it means zero error is-26 divisions on the circular scale. If the negativeZero error of screw gauge is x mm, the value of x is………..