A Screw gauge of pitch 0.5mm is used to measure the diameter of uniform wire of length 6.8cm, the head scale reading is 1.5mm and circular scale reading is 7. The calculated curved surface area of wire is (Screw gauge has 50 divisions)_____ $c m^{2}$
(Round off to nearest integer)

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answer is 3.

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Detailed Solution

$= 1.5 m m + \frac{0.5}{50} \times 7 m m$

$= 1.57 m m$

Surface area $A = 2 π r l$

$= π \times D \times l$

$= 3.14 \times 1.57 \times 10^{- 3} \times 6.8 \times 10^{- 2}$

$= 33.5 \times 10^{- 5}$

$= 3.35 \times 10^{- 6}$

$= 3.4 \times 10^{- 6} = 3.4 c m^{2}$

$≃ 3 c m^{2}$

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