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A sealed flask with a capacity of 2 dm³ contains 11 g of propane gas. The flask is so weak that it will burst if the pressure becomes 2 MPa. The minimum temperature at which the flask will burst is _______ °C. [Nearest integer] (Given: R = 8.3 J K^–1 mol^–1. Atomic masses of C and H are 12u and 1u respectively.) (Assume that propane behaves as an ideal gas.)

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answer is 1655.

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Detailed Solution

Moles of $C_{3} H_{8} = \frac{11}{44} = 0 .25 moles$

PV = nRT

$\begin{array}{l} \Rightarrow 2 \times 10^{6} \times 2 \times 10^{- 3} = 0 .25 \times 8 .3 \times T \\ \Rightarrow T = 1927 .710 K = 1654 {.56}^{\circ} C \end{array}$

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