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A sealed packet of volume $350 {cm}^{3}$ is inside the water. The mass of the water, [[1]], $g$ is replaced by the packet.

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Detailed Solution

A sealed packet of volume

350 {cm}^{3}

is inside the water. The mass of the water,

350 g

, is replaced by the packet.
Given that,

volume of the packet = 350 {cm}^{3}

We know the density of the water is

1 gm / {cm}^{3}

From the relation of mass, volume and density,

Mass of water = volume of displace water \times density of water

On putting all the values in the above relation we get,

\Rightarrow Mass of the water replaced = 350 \times 1

\Rightarrow Mass of the water replaced = 350 g

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