A semi circular current carrying wire having radius R is placed in x-y plane with its centre at origin ‘O’. There is non-uniform magnetic field $\vec{B} = \frac{B_{0} x}{2 R} \hat{k}$ (here $B_{0}$ is $+ ve$ constant) is existing in the region. The magnetic force acting on semi circular wire will be along

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answer is A.

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Detailed Solution

B = \frac{B_{0} x}{2 R} \hat{k}

To the left of y – axis, B is into the plane of the paper .

To the right of y – axis, B is out of the plane of the paper

Net force along y – axis = 0

$∴$ The resultant force is along – ve x – axis

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