A series circuit has a resistance of $60 Ω$ and impedance $100 Ω$ . If p.d. applied across the circuit is 120 V, the power consumed in the circuit will be

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864 W

480 W

86.4 W

240 W

answer is A.

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Detailed Solution

$\begin{aligned} P = V i \cos θ = V \times \frac{V}{Z} \times \frac{R}{Z} \\ = \frac{120 \times 120 \times 60}{100 \times 100} = 86.4 W \end{aligned}$

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