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Q.

A series L-C-R circuit R = 10 kΩ, L = 20 mH, C = 5 μF is connected to AC source V = 10sin ωt. Find out bandwidth of signal.

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a

100 kHz

b

120 kHz

c

80 kHz

d

800 kHz

answer is A.

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Detailed Solution

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∆f=R2πL=10kΩ2π x 20 x 10-3H=5002πk=80 kHz

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