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Q.

A series LCR circuit is connected to a  45sinωt Volt source. The resonant angular frequency of the circuit is  105rads1 and current amplitude at resonance is I0.  When the angular frequency of the source is ω=8×104rads1,  the current amplitude in the circuit is  0.05I0. If L=50mH, match each entry in List-I with an appropriate value from List-II and choose the correct option.
 

 List-I List-II
(P)I0 in mA(1)44.4
(Q)The quality factor of the circuit  (2)18
(R)The bandwidth of the circuit in rads1(3)400
(S)The peak power dissipated at resonance in Watt (4)2250
  (5)500

 

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a

P3,Q1,R4,S2

b

P4,Q5,R3,S1

c

P4,Q2,R1,S5

d

P2,Q3,R5,S1

answer is B.

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Detailed Solution

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ω0=1LCC=2×109F I0=V0R5100I0=V0R2+XLXC2 R=9×1034399ΩR112.5Ω I0=V0R=400mAQ=1RLC=44.4 Q=ωr. Band width  Bandwidth =ωrQ  Peak power =V02R=18 watt 

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