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Q.

A series LCR circuit is connected to a source of alternating voltage of angular frequency ω. Which of the following statements is/are TRUE if ω=1LC and FALSE if ω1LC?

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a

The capacitor is uncharged at the instant the current in the circuit reaches its maximum value

b

The rms potential difference across the capacitor is equal to the rms EMF induced across the Inductor

c

The rate of heat dissipation is maximum at the instant the current is maximum 

d

The combined energy stored in the capacitor and the inductor remains constant

answer is B, D.

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Detailed Solution

The circuit is in resonance when ω=1LC.

Therefore, we are being asked which statements are true ONLY when the circuit is in resonance and not otherwise. 

(A) The charge on the capacitor (or the potential difference across it) is always behind the current in the circuit by a phase angle π2. This is true for any LCR circuit, for any frequency.

(B) The rms potential difference across the capacitor is (VC)RMS=IRMSXC=IRMSωC

The rms induced emf across the inductor is (VL)RMS=IRMSXL=IRMSωC

We can see that these quantities are equal only when ω=1LC and not otherwise

(C) Since heat is only dissipated in the resistance, the rate of dissipation is HI2R. This is always true, not only at resonance

(D) Let the instantaneous current be I(t)=I0sin(ωt)

Here, I0 is the maximum value of the current and it is a constant

Then, we know that the instantaneous potential difference across the capacitor, VC(t)=I0ωCsin(ωtπ2)=I0ωCcos(ωt)

The instantaneous energy stored in the capacitor, UC(t)=12CVC2=12I02ω2Ccos2(ωt)

The instantaneous energy stored in the inductor, UL(t)=12LI2==12LI02sin2(ωt)=12LI02(1cos2(ωt))

Hence, the total energy stored in both U(t)=UC(t)+UL(t)=12LI02+12I02(1ω2CL)cos2(ωt)

We can see that U(t) remains constant with time only if 1ω2CL=0, i.e. at resonance.

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