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A shallow glass dish is 4.00 cm wide at the bottom as shown in figure. When an observer’s eye is positioned as shown, the observer sees the edge of the bottom of the empty dish. When this dish is filled with water, the observer sees the centre of the bottom of the dish. The height of the dish is $x \times 10^{- 1}$ cm $(μ_{w} = 4 / 3) .$ Then $x$ is

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Detailed Solution

Applying, $μ = \frac{\sin i}{\sin r} we get \frac{4}{3} = \frac{4 / \sqrt{16 + h^{2}}}{2 / \sqrt{4 + h^{2}}}$
Solving this equation we get, $h = 2.4 cm$

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