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A sheet ABCD has mass M. Sides AB and CD are parallel to each other and perpendicular to BC. The perpendicular distance of mid point of AD from side BC is half of length of BC, then moment of inertia of sheet about axis AD is

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$\frac{M l^{2}}{3}$

$\frac{M l^{2}}{2}$

$\frac{M l^{2}}{12}$

$\frac{4 M l^{2}}{3}$

answer is C.

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Detailed Solution

Plate is half of square plate $S o, I = \frac{M l^{2}}{12}$

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