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Q.

A shell is fired from a gun from the bottom of a hill along its slope. The slope of the hill is α = 30°, the angle of the barrel to the horizontal β = 60°. The initial velocity v of the shell is 21 m/s. Then, the distance of point from the gun at which shell falls is

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a

30 m

b

40 m

c

10 m

d

20 m

answer is C.

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Detailed Solution

Here, u = 21 m/s, α=30∘,θ=(β−α)
=60∘−30∘=30∘
Maximum range
R=2u2gsin⁡θcos⁡(θ+α)cos2⁡α=2×(21)2×sin⁡30∘cos⁡60∘9.8×cos2⁡30∘=30m

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