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A shell of mass m is fired from a cannon at angle $θ$ to the horizontal with a velocity v. The shell at the highest point breaks into two fragments having masses in the ratio 2 : 3.The heavier fragment has a velocity zero immediately after explosion and falls vertically downward, the velocity of the other fragment just after explosion is

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5v cos $θ$

3v cos $θ$

$\frac{2}{5}$ v cos $θ$

$\frac{5}{2}$ v cos $θ$

answer is D.

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Detailed Solution

Linear momentum of the system in horizontal direction is conserved

$5 mv cosθ = 0 + 2 m_{2} v_{2} = \frac{5}{2} vcosθ$

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