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A ship A is moving Westwards with a speed of 10 km h^–1 and a ship B 100 km South of A, is moving Northwards with a speed of 10 km h^–1. The time after which the distance between them becomes shortest,is

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0 h

5√2h

10√2h

5 h

answer is D.

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Detailed Solution

$V_{A} = 10 (- i); V_{B} = 10 (\vec{j}); V_{B A} = 10 \vec{j} + 10 \vec{i}; V_{B A} = 10 \sqrt{2} Km / h$

Time taken to reach the shortest distance between A and B

$= \frac{O B}{V_{B A}} = \frac{50 \sqrt{2}}{10 \sqrt{2}} = 5 h$

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