A ship is travelling due east at 10 km/h. A ship heading 30° east of north is always due north from the first ship. The speed of the second ship in km/h is

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$20 \sqrt{2}$

$20 \sqrt{3 / 2}$

$20 / \sqrt{2}$

answer is C.

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Detailed Solution

${\vec{V}}_{A} = 10 \overset{\land}{i}, {\vec{V}}_{B} = V_{B} \sin 30 \overset{\land}{i} + V_{B} \cos 30 \overset{\land}{j} {\vec{V}}_{B A} = V_{B A} \overset{\land}{j} 10 = V_{B} \sin 30 10 = V_{B} \times \frac{1}{L} \Rightarrow V_{B} = 20$

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