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Q.

A short bar magnet has a magnetic moment of 0.39 ${JT}^{- 1}$ . The magnitude and direction of the magnetic field produced by the magnet at a distance of 20cm from the center of the magnet on the equatorial line of the magnet is

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a

0.049 G, N-S direction

b

4.9 G, S-N direction

c

0.0195 G, S-N direction

d

19.5 G, N-S direction

answer is A.

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Detailed Solution

Concept: We must determine the amplitude and direction of the magnetic field created by the short bar magnet in order to answer the issue. The radius will be 0.2m if the magnetic moment is 0.39JT and the diameter is 20cm. Magnetism along the equatorial line
By using the formula we get
Hence, option 1 is correct.

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