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A short bar magnet is oscillating in a magnetic field and its time period is 2 seconds . If another piece of brass of double moment of inertia be placed over that magnet the time period of that combination in that field is

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2 $\sqrt{3}$ S

2 $\sqrt{2}$ S

2 S

1 $\sqrt{2}$ S

answer is A.

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Detailed Solution

$T = 2 π \sqrt{\frac{I}{M B_{H}}} and \frac{T_{1}}{T_{2}} = \sqrt{\frac{I_{1}}{I_{2}}} = \sqrt{\frac{l}{3 /}} = \frac{1}{\sqrt{3}}$

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