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Q.

A short bar magnet is placed in the magnetic meridian of earth with north pole pointing north. Neutral points are found at a distance of 30 cm from the magnet on the East-West line, drawn through the middle point of the magnet. The magnetic moment of the magnet in Am2 is close to Given  μo4π=107  inSI  units  and  BH=Horizontalcomponent  ofearth's  magneticfield=3.6×105  tesla

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a

4.9

b

14.6

c

19.4

d

9.7

answer is C.

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Detailed Solution

Bequa =BH=μ04πmr3 3.6×105=107×m(0.30)3 m=3.6×105×(0.30)3107=9.72Am2

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A short bar magnet is placed in the magnetic meridian of earth with north pole pointing north. Neutral points are found at a distance of 30 cm from the magnet on the East-West line, drawn through the middle point of the magnet. The magnetic moment of the magnet in Am2 is close to Given  μo4π=10−7  in SI  units  and  BH=Horizontal component  of  earth's  magnetic field=3.6×10−5  tesla