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Q.

A short bar magnet used in a vibration magnetometer is heated so as to reduce its magnetic moment by 36%, then the frequency of magnet is (Neglecting the Changes in the dimensions of the magnet)

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a

Increase by 20%

b

Decreases by 36%

c

Increase by 36%

d

Decreases by 20%

answer is D.

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Detailed Solution

 Time period, T=2πIMBH

Frequency, f=12πMBHI

⇒f1 f2=M1M2

 If M1=100 then, M2=(100-36)=64

 So, f1 f2=10064=108

f2=810 f1=0.8f1

 So, % decrease in frequency=20% 

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