Q.

A short electric dipole has a dipole moment of  32×109 Cm. The electric potential due to the dipole at a point at a distance of 0.18 m from the centre of the dipole, situated on a line making an angle of 60o with the dipole axis is : 14πε0=9×109Nm2/C2

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a

200 V

b

400 V

c

800 V

d

Zero

answer is A.

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Detailed Solution

V=Kp cos θr2=9×109×32×109×12×0.18=9×322×0.18=9×322×18=800 V

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