A silver ball of radius 4.8 cm is suspended by the tread in the vacuum chamber. UV light of waves length 200 nm is incident on the ball for some times during which a total energy of 1×10−7J falls on the surface. Assuming on an average one out of 103 photons incident is able to eject electron. The potential on sphere will be

n=Eλhc=1×10−7×200×10−96.6×10−34×3×108=1×1011Number of electrons ejected = 1011103=108∴v=q4πε0r =(108×1.6×10−19)×9×1094.8×10−2=3 V

A silver ball of radius 4.8 cm is suspended by the tread in the vacuum chamber. UV light of waves length 200 nm is incident on the ball for some times during which a total energy of 1×10−7J falls on the surface. Assuming on an average one out of 103 photons incident is able to eject electron. The potential on sphere will be

n=Eλhc=1×10−7×200×10−96.6×10−34×3×108=1×1011Number of electrons ejected = 1011103=108∴v=q4πε0r =(108×1.6×10−19)×9×1094.8×10−2=3 V

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A silver ball of radius 4.8 cm is suspended by the tread in the vacuum chamber. UV light of waves length 200 nm is incident on the ball for some times during which a total energy of $1 \times 10^{- 7} J$ falls on the surface. Assuming on an average one out of $10^{3}$ photons incident is able to eject electron. The potential on sphere will be

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Detailed Solution

$n = \frac{E λ}{h c} = \frac{1 \times 10^{- 7} \times 200 \times 10^{- 9}}{6.6 \times 10^{- 34} \times 3 \times 10^{8}} = 1 \times 10^{11}$

Number of electrons ejected = $\frac{10^{11}}{10^{3}} = 10^{8}$

$∴ v = \frac{q}{4 π ε_{0} r} = \frac{(10^{8} \times 1.6 \times 10^{- 19}) \times 9 \times 10^{9}}{4.8 \times 10^{- 2}} = 3 V$

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