A silver rod of length 1 m at 0 0C is heated to 100 0C. It’s length is increased by 0.19 cm. Coefficient of cubical expansion of silver is

Co-efficient of linear expansion is α =ΔllΔt=0.0019100=1.9×10−5 /∘CCoefficient of volume expansion is 3α=5.7×10−5/∘C

A silver rod of length 1 m at 0 0C is heated to 100 0C. It’s length is increased by 0.19 cm. Coefficient of cubical expansion of silver is

Co-efficient of linear expansion is α =ΔllΔt=0.0019100=1.9×10−5 /∘CCoefficient of volume expansion is 3α=5.7×10−5/∘C

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A silver rod of length 1 m at 0 ⁰C is heated to 100 ⁰C. It’s length is increased by 0.19 cm. Coefficient of cubical expansion of silver is

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$16.1 \times 10^{- 5} /^{0} C$

$1.9 \times 10^{- 5} /^{0} C$

$5.7 \times 10^{- 5} /^{0} C$

$0.63 \times 10^{- 5} /^{0} C$

answer is A.

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Detailed Solution

Co-efficient of linear expansion is $α = \frac{Δ l}{l Δt} = \frac{0.0019}{100} = 1.9 \times 10^{- 5} /^{\circ} C$
Coefficient of volume expansion is $3 α = 5.7 \times 10^{- 5} /^{\circ} C$

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A silver rod of length 1 m at 0 0C is heated to 100 0C. It’s length is increased by 0.19 cm. Coefficient of cubical expansion of silver is

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A silver rod of length 1 m at 0 ⁰C is heated to 100 ⁰C. It’s length is increased by 0.19 cm. Coefficient of cubical expansion of silver is