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Q.

A simple harmonic oscillator has a period of 0.01 sec and an amplitude of 0.2 m. The magnitude of the velocity in msec−1  at the centre of oscillation is

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a

100

b

100π

c

40π

d

20π

answer is C.

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Detailed Solution

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At centre vmax=aω=a.2πT=0.2×2π0.01=40π

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