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Q.

A simple harmonic oscillator has a time period of 2 sec. The change in phase 0.5 sec after leaving the mean position is (in radian)

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a

π

b

$\frac{π}{2}$

c

$\frac{π}{3}$

d

$\frac{π}{4}$

answer is B.

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Detailed Solution

$ϕ = \frac{2 π}{2} \times t = \frac{2 π}{2} \times 0 .5 = \frac{π}{2} rad$

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A simple harmonic oscillator has a time period of 2 sec. The change in phase 0.5 sec after leaving the mean position is (in radian)