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Q.

A simple harmonic wave is travelling along a straight line. The distance between two points in same phase is 5m, while the distance between two points in opposite phase is 1.5m. What can be the wavelength of the wave? 
A) 0.5m          B)1m          C) 1/3m         D) 1/7m

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a

BCD

b

B

c

C

d

D

answer is D.

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Detailed Solution

nλ=5⇒λ=5n,(2m−1)π2=1.5m ⇒ λ=32m−1

'λ' must satisfy both λ=5n  and  λ=32m−1

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