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A simple pendulum consisting of a ball of mass m tied to a thread of length l is made to swing on a circular arc of angle $θ$ in a vertical plane. At the end of this arc, another ball of mass m is placed at rest. The momentum transferred to this ball at rest by the swinging ball is

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$\frac{mθ}{l} \sqrt{\frac{l}{g}}$

$\frac{m}{l} 2 π \sqrt{\frac{l}{g}}$

Zero

$mθ \sqrt{\frac{g}{l}}$

answer is A.

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Detailed Solution

No momentum will be transferred because, at extreme position the velocity of bob is zero.

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