Q.

A simple pendulum has a time period T1 when it oscillates on the earth’s surface and T2  when it is taken to a height ‘R’ above the earth’s surface, where ‘R’ is the radius of the earth. The value of T2/T1 is

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a

4

b

1

c

2

d

2

answer is D.

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Detailed Solution

T1=2πlg;T2=2πlgh

gh=g(RR+h)2=g(RR+R)=g4

T2T1=ggh=g4

T2T1=ggh=4=2

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