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Q.

A simple pendulum has time period T1. The point of suspension is now moved upward according to equation y=kt2  where k=1m/sec2. If new time period is T2 then ratio T12T22  will be

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a

5/6

b

3/2

c

2/3

d

6/5

answer is C.

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Detailed Solution

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y=Kt2d2ydt2=ay=2K=2×1=2m/s2K=1m/s2
Now, T1=2πlg and  T2=2πl(g+ay)
Dividing, T1T2=g+ayg65T12T22=65

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